\h fSSKJrJr SSKJr SSKJr SSKJrJ r SSK J r SSK J r SrSrS rg ) )FunctionDefinedFunctionsympify)tanh)cossin)limit)xc"[[4Hn"SSU5nU"[5R[SS5[ [5R[SS5:Xde[ U"[5[- [S5S:XaMe g)zCreate our new "sin" function.c.\rSrSrSSjr\S5rSrg)*test_function_series1..my_functionc2[URS5$Nr)rargsselfargindexs g/var/www/auris/envauris/lib/python3.13/site-packages/sympy/functions/elementary/tests/test_interface.pyfdiff0test_function_series1..my_function.fdiffs499Q<((c<[U5nUS:Xa [S5$grrclsargs reval/test_function_series1..my_function.eval!cl!8"1:%rN__name__ __module__ __qualname____firstlineno__r classmethodr__static_attributes__r!rr my_functionrs ) & &rr+r r#N)rrr seriesr r )Fr+s rtest_function_series1r/ss ( &! &1~$$Q2.#a&--1b2IIII[^A%q!,111)rc[[4HWn"SSU5nU"[5R[SS5[ [5R[SS5:XaMWe g)zCreate our new "cos" function.c.\rSrSrSSjr\S5rSrg)+test_function_series2..my_function2)c4[URS5*$r)r rrs rr1test_function_series2..my_function2.fdiff+sDIIaL)))rc<[U5nUS:Xa [S5$g)Nrr#rrs rr0test_function_series2..my_function2.eval.r rr!Nr"r$r!rr my_function2r2)s * & &rr8rr,N)rrr r-r)r.r8s rtest_function_series2r9$sS ( &1 &A%%aB/3q6==Ar3JJJJ)rc^[[4H^n"U4SjSU5m[[5nT"[5nUR [SS5UR [SS5:XaM^e g)aC Test our easy "tanh" function. This test tests two things: * that the Function interface works as expected and it's easy to use * that the general algorithm for the series expansion works even when the derivative is defined recursively in terms of the original function, since tanh(x).diff(x) == 1-tanh(x)**2 c6>\rSrSrSU4Sjjr\S5rSrg)%test_function_series3..mytanhEc:>ST"URS5S-- $)Nr#r)r)rrmytanhs rr+test_function_series3..mytanh.fdiffGs 6$))A,/222rc<[U5nUS:Xa [S5$grrrs rr*test_function_series3..mytanh.evalJr rr!Nr"r$)r@srr@r<Es 3 & &rr@rN)rrrr r-)r.efr@s @rtest_function_series3rG8s\ ( &Q & G 1Ixx1a AHHQ1$5555)rN)sympy.core.functionrrsympy.core.sympifyr%sympy.functions.elementary.hyperbolicr(sympy.functions.elementary.trigonometricrr sympy.series.limitsr sympy.abcr r/r9rGr!rrrNs):&6?%2*K(6r